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Question

The centripetal force required for a $$1000 kg$$  car traveling  at  $$36 kmph $$ to take a turn by $$90^o $$ in traveling along an arc of length $$628 m $$ is 


A
250N
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B
500N
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C
1000N
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D
125N
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Solution

The correct option is C $$250 N $$

The radius of arc is,

$$\dfrac{{\pi r}}{2} = 628$$

$$r = \dfrac{{628 \times 2}}{\pi }$$

$$r = 400\;{\rm{m}}$$

velocity in $$\rm{m/s}$$ is,

$$v = 36\;{\rm{km/h = 36}} \times \dfrac{5}{{18}} = 10\;{\rm{m/s}}$$

Centripetal force will be,

$$F = \dfrac{{m{v^2}}}{r}$$

$$F = \dfrac{{1000 \times {{10}^2}}}{{400}}$$

$$F = 250{\rm{N}}$$

Thus, centripetal force is $$250{\rm{N}}$$.


Physics

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