Question

# The centripetal force required for a $$1000 kg$$  car traveling  at  $$36 kmph$$ to take a turn by $$90^o$$ in traveling along an arc of length $$628 m$$ is

A
250N
B
500N
C
1000N
D
125N

Solution

## The correct option is C $$250 N$$The radius of arc is,$$\dfrac{{\pi r}}{2} = 628$$$$r = \dfrac{{628 \times 2}}{\pi }$$$$r = 400\;{\rm{m}}$$velocity in $$\rm{m/s}$$ is,$$v = 36\;{\rm{km/h = 36}} \times \dfrac{5}{{18}} = 10\;{\rm{m/s}}$$Centripetal force will be,$$F = \dfrac{{m{v^2}}}{r}$$$$F = \dfrac{{1000 \times {{10}^2}}}{{400}}$$$$F = 250{\rm{N}}$$Thus, centripetal force is $$250{\rm{N}}$$.Physics

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