Question

The centroid of the triangle whose vertices are (1, 3) (2, 7) and (12, -16) is given as (a, b). Find a+b.

• A. 3

Answer 1

The correct option is A 3

$\text{Centroid of the triangle}$

$=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})$

$=(\frac{1+2+12}{3},\frac{3+7+(-16)}{3})$

$=(\frac{15}{3},\frac{10-16}{3})$

$=(5,\frac{-6}{3})$

$=(5,-2)$

Comparing it to (a, b), a = 5, b = -2.

So, a+b = 5 - 2 = 3