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Question

The CFSE for octahedral [CoCl6]4 is 18,000cm1. The CFSE for tetrahedral [CoCl4]2 will be:

A
18,000cm1
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B
16,000cm1
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C
8,000cm1
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D
20,000cm1
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Solution

The correct option is C 8,000cm1
Δt=49×Δo

Where Δt= CFSE for tetrahedral complex.

Δo= CFSE for octahedral complex.

Δt=49×(18,000 cm1)=8000 cm1

Hence option C is correct.

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