Question

The chainage of the intersection point of two straight lines is 1585.60 m and the angle of intersection is ${40}^{\circ }$. If the radius of a circular curve is 600 m, the tangent distance (in m) and length of the curve (in m) are -

• A. 418.88 & 1466.08
• B. 218.38 & 418.88
• C. 218.38 & 1648.45
• D. 418.88 & 218.38

Answer 1

The correct option is B 218.38 & 418.88



$Lengthoftangent,T=600\tan {20}^{\circ }$

$=218.38m$

$Lengthofcurve=2\pi R\times \left(\frac{{40}^{\circ }}{{360}^{\circ }}\right)$

$=2\times \pi \times 600\times \frac{1}{9}=418.88m$

Hence, option (c) is correct.