Question

The chance of throwing sum of $3$ or $5$ or $11$ with a pair of die is

• A. $\frac{2}{9}$
• B. $\frac{5}{9}$
• C. $\frac{1}{9}$
• D. $\frac{5}{36}$

Answer 1

The correct option is A $\frac{2}{9}$

$\left(A\right)=\{(1,2),(2,1)(1,4)(2,3),(3,2),(4,1),(5,6),(6,5)\}$
$\therefore n\left(A\right)=8$
and $n\left(S\right)=36$
$\therefore P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}=\frac{8}{36}=\frac{2}{9}$