Question

The chances of throwing a total of $3$ or $5$ or $11$ with two dice is

• A. $\frac{5}{36}$
• B. $\frac{1}{9}$
• C. $\frac{2}{9}$
• D. $\frac{19}{36}$

Answer 1

The correct option is C

$\frac{2}{9}$

Explanation for the correct option

Finding the possibility

The possibilities for a total of $3$ or $5$ or $11$ with $2$ dice are:

$(1+2),(2+1),(1+4),(2+3),(3+2),(4+1),(5+6),(6+5).$

So, there are a total of 8 favourable outcomes.

The total possible outcomes of throwing two dice together will be $=36$

Therefore, the probability will be,

$$\begin{gathered} =\frac{\mathrm{Favourable}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{outcomes}} \\ =\frac{8}{36} \\ =\frac{2}{9} \end{gathered}$$
Hence, the correct answer is option (C).