MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Work

The change in...

Question

The change in internal energy of two moles of a gas during adiabatic expansion is found to be $- 100 J$ . The work done during the process is

A

- 100 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

0 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

100 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

200 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $100 J$
The process is adiabatic which implies that $d Q = 0$ .
Thus using first law $- d W = d U ⟹ W = 100 J$

Suggest Corrections

thumbs-up

0

Similar questions

Q. During an adiabatic expansion of

2 m o l e s

of a gas, the change in internal energy was found to be equal to

- 200 J

. The work done during the process will be equal to

Q. During the adiabatic expansion of two moles of a gas the internal energy of a gas is found to decrease by

2

joules. The work done during the process on the gas will be equal to:

Q. During an adiabatic expansion of

5 m o l e s

of gas, the internal energy decreases by

75 J

. The work done during the process is

Q. During the adiabatic expansion of 2 moles of a gas, the internal energy of the gas is found to decrease by 2 joules, the work done during the process on the gas will be equal to

Q. A system undergoes a process in which system releases 200 J heat and work done by the surroundings is 300 J. Change in internal energy of the system is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

The First Law of Thermodynamics

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon