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Gravtiational PE

The change in...

Question

The change in kinetic energy per unit 'space' (distance) is equal to:

A

power

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B

momentum

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C

force

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D

pressure

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Solution

The correct option is B force
$\frac{d (K . E)}{d s} = \frac{d (\frac{1}{2} m v^{2})}{d s}$

$= m v \times \frac{d v}{d s}$

$= m a =$ Force

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