Question

The change in the value of acceleration of earth towards sun, when the moon comes from the position of solar eclipse to the position on the other side of earth in line with sun is.
(mass of moon = 7.36 1022 kg, orbital radius of moon = $3.8\times 108$m.)

• A. $6.73\times {10}^{2}m/s^2$
• B. $6.73\times {10}^{-3}m/s^2$
• C. $6.73\times {10}^{4}m/s^2$
• D. $6.73\times {10}^{-5}m/s^2$

Answer 1

The correct option is D $6.73\times {10}^{-5}m/s^2$

$\text{Acceleration of earth due to moon}=\frac{G{M}_{moon}}{r_{orbital}^2}$

Thus the change in acceleration due to two opposite orientations of earth is,

$\frac{2G{M}_{moon}}{r_{orbital}^2}=6.73\times {10}^{-5}{\text{m/s}}^2$