Question

The change of throwing an ace first only of two successive throws with an ordinary die is

• A. $\frac{1}{36}$
• B. $\frac{5}{36}$
• C. $\frac{25}{36}$
• D. $\frac{1}{6}$

Answer 1

The correct option is B $\frac{5}{36}$

$\therefore$ Probability of throwing an ace $=\frac{1}{6}$ and of
not throwing ace $=\frac{5}{6}.$ Hence, required
probability $=\frac{1}{6}\times \frac{5}{6}=\frac{5}{36}.$