The charge in coulombs of 1 gram ion of $N^{3 -}$ is (the charge on an electron is $1.602 \times 10^{- 19} C$ )

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Solution

We have,
$charge on one electron = 1.6 x 10^{- 19} C so, charge on 1 mole of N^{3 -} = 3 x 1.6 x 10^{- 19} C so charge on 14 g of N^{3 -} = 3 \times 1.6 \times 10^{- 19} C so, charge on 1 g of N^{3 -} = \frac{3}{14} \times 1.6 \times 10^{- 19} C = 3.4 \times 10^{- 20} C$

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