The charge of an electron is known to be 1.6×10−19 C. In a circuit, the current flowing is 1 A. How many electrons will be flowing through the circuit per second?
0.625 x 1019
We know that, current, I = Qt = net
I = n×1.6×10−191
n=11.6×10−19
Solving we get,
n = 6.25×1018