The charge of calcium in $C a C l_{2}$ is:

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-1

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-2

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Solution

The correct option is E 2
Charge of Calcium in $C a C l_{2} = + 2$
So, Calcium ion exists as $C a^{2 +}$ and chlorine ion exists as $C l^{-}$ , so its $C a C l_{2}$ .

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