Question

The charge on $500cc$ of water due to proton will be

• A. $6.1\times {10}^{27}C$
• B. $2.67\times {10}^{7}C$
• C. $6\times {10}^{23}C$
• D. $1.67\times {10}^{23}C$

Answer 1

Answer: (B)

$2.67\times {10}^{7}C$

$500cc=500ml=500g$

So,

the number of moles of water $=500$ / atomic weight $=500/18=27.78$ moles

Thus, the number of molecules would be $=$ No. of moles $\times$ Avogadro's No.

or, the total no. of molecules $=27.78\times 6.023\times {10}^{23}$

$=1.67\times {10}^{25}$

and each water molecules has $10$ protons in it.

Thus, total no. of protons in $500cc$ of water would be $=$ total number of molecules $\times 10=1.67\times {10}^{26}$ protons.

the total protonic charge $=$ number of protons $\times$ protonic charge

$Q=ne$

$=1.67\times {10}^{26}\times 1.6\times {10}^{-19}C$

Total charge due to protons in $500cc$ of water

$Q=2.67\times {10}^{7}C$