Question

The charge on 500 cc of water due to protons will be

• A. $6.0\times {10}^{27}C$
• B. $2.67\times {10}^{7}C$
• C. $6\times {10}^{23}C$
• D. $1.67\times {10}^{23}C$

Answer 1

The correct option is B $2.67\times {10}^{7}C$

Given,

Volume of water = 500 cc = 500 ml = 500 g

So, Number of moles = $\frac{500}{atomicweight}=\frac{500}{18}=27.78moles$

Total number of molecules = $Moles\times Avogadr{o}^{\prime }snumber=27.78\times 6.023\times {10}^{23}=1.67\times {10}^{25}$

We know that each water molecules have 10 protons

Now we can write,

Total number of proton = $1.67\times {10}^{26}$

Now,

Total charge = $Q=ne=1.67\times {10}^{26}\times 1.6\times {10}^{-19}=2.67\times {10}^{7}C$

Hence total charge on the water = $2.67\times {10}^{7}C$