Question

The charge on a particle is $100$ times that of electron. It is revolving in a circular path of radius $0.8m$ at a frequency of ${10}^{th}$ revolutions per second. The magnetic field at the centre of path will be -

• A. ${10}^{-16}{\mu }_0$
• B. $\frac{{10}^{-7}}{\mu }$
• C. ${10}^{-17}\mu$
  
• D. ${10}^{-6}\mu$

Answer 1

The correct option is A ${10}^{-16}{\mu }_0$

$\begin{array}{c}T=0.1\sec \\ i=\frac{100\times e}{0.1}=1000e\\ B=\frac{\mu oi}{2r}=\frac{{\mu }_0\times 1000\times 1.6\times {10}^{-19}}{2\times 0.8}\\ ={10}^{-16}{\mu }_0\end{array}$