Question

The charge on the $4\mu F$ capacitor in the steady states is

• A. $\frac{20}{3}\mu C$
• B. $\frac{10}{3}\mu C$
• C. $\frac{5}{6}\mu C$
• D. $10\mu C$

Answer 1

Answer: (A)

$\frac{20}{3}\mu C$

At steady state

$I=\frac{10}{5+5}=1A{V}_{5\Omega }=5\times 1=5V$

Voltage across $4\mu C$ is

$V_4=\frac{5\times 2}{4+2}=\frac{10}{6}=\frac{5}{3}V$

Charge is

$Q=4\times \frac{5}{3}=\frac{20}{3}\mu C$