Question

The charge on the electron and proton is reduced to half. Let the present value of the Rydberg constant be $R$. What will be the new value of the Rydberg constant?

• A. $R/2$
• B. $2R$
• C. $4R$
• D. $R/16$

Answer 1

The correct option is D $R/16$

Rydberg constant is given by
$R\propto e^4$, where $e$ is the elementary charge
If $e$ is reduced to $e/2$,
$R^{\prime }=e^4/16$
$R^{\prime }=R/16$