Question

The charge required for the oxidation of one mole $M{n}_3{O}_4$ into $MnO{{}_4}^{2-}$ in presence of alkaline medium is :

• A. $5\times 96500C$
• B. $96500C$
• C. $10\times 96500C$
• D. $2\times 96500C$

Answer 1

Answer: (C)

$10\times 96500C$

The oxidation states of manganese in ${Mn}_3{O}_{4}andMn{O}_4^{2-}$ are $\left(\frac{8}{3}\right)$ and 6 respectively.

Thus the oxidation of one mole of ${Mn}_3{O}_4$ to $Mn{O}_4^{2-}$ will require 10 $\left(\right(6-\frac{8}{3})\times 3)$ moles of electrons or $10\times 96500C$.

Option C is correct.