The charge required for the reduction of 1 mole of $M n O_{4}^{-}$ to $M n O_{2}$ is

1 F

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3 F

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5 F

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7 F

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Solution

The correct option is B 3 F
$1 F = 96500 C$ is the charge required to change the oxidation number by one unit.
1 mole of $M n O_{4}^{-}$ gets reduced to $M n O_{2}$ ,
Change in oxidation number= +7 $\to$ +4 = 3
Hence, $3 F$ charge is required for the reduction of $M n O_{4}^{-}$ to $M n O_{2}$

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