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Question

The charge required to deposit 9 g of Al from an Al3+ solution is:

A
32166.3 C
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B
96500 C
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C
3216.33 C
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D
9650 C
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Solution

The correct option is B 96500 C
Al3++3eAl

The atomic mass of Al=27 g/mol
9g of Al=927=0.333 moles

1 mole Al= 3 moles electrons.
0.333 moles Al=0.333×3=1 mole electrons

1 mole electrons =1 faraday of electricity =95000 C.

Hence, option (B) is the correct answer.

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