Question

The charge supplied by the battery in the circuit shown in the figure is-

• A. $110\mu \text{C}$
• B. $140\mu \text{C}$
• C. $150\mu \text{C}$
• D. $120\mu \text{C}$

Answer 1

The correct option is C $150\mu \text{C}$

As we can see, all three capacitors are in parallel to the battery.


Let, charge on $4\mu \text{F},5\mu \text{F}$ and $6\mu \text{F}$ be $q_1,q_2$ and $q_3$ respectively.

$q_1=C_{1}V=4\times 10=40\mu \text{C}$

$q_2=C_{2}V=5\times 10=50\mu \text{C}$

$q_3=C_{3}V=6\times 10=60\mu \text{C}$

Net charge through the circuit is,

$q=q_1+q_2+q_3=40+50+60=150\mu \text{C}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(C\right)$ is the correct answer.