The charges q1 nbsp- 2 mu-C and q2 nbsp- -4 mu-C are located at coordinates -1- -1- and -3- 2- respectively- If we have put one more charge q3 nbsp- 8 mu-C in the line joining the two charges such that the charges maintain an equilibrium- then find the coordinate of the location of q3-

Dear student let #160;the #160;cordinate #160;of #160;3 #160;charge #160;be #160;r #8640; #160; #160;from #160;2 #160; #160; #956;C ...

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Byju's Answer

Standard XII

Physics

Electric Potential at a Point in Space Due to a Point Charge Q

The charges q...

Question

The charges q1 = 2 μC and q2 = -4 μC are located at coordinates (-1, -1) and (3, 2) respectively. If we have put one more charge q3 = 8 μC in the line joining the two charges such that the charges maintain an equilibrium, then find the coordinate of the location of q3.

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Solution

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$l e t t h e c o r d i n a t e o f 3 c h a r g e b e \overset{⇀}{r} f r o m 2 μ C c h a r g e h e n c e t h e f o r c e b e t w e e n 2, 8 μ C i s e q u a l t o - 4 a n d 8 μ C u \sin g c o u l o m b s f o r c e i n v e c t o r f o r m {\overset{⇀}{F}}_{2, 8} = {\overset{⇀}{F}}_{- 4, 8} \frac{k \times 2 \times 8 \times}{(r)^{2}} = \frac{k \times 4 \times 8}{(5 + r)^{2}} r = 12.19 n o w s l o p e o f l i n e \tan θ = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{3}{4} h e n c e x c o r d i n a t e w i l l b e - (1 + r \cos θ) = - (1 + 12.19 \times \frac{4}{5}) = - 10.75 h e n c e x c o r d i n a t e w i l l b e - (1 + r \sin θ) = - (1 + 12.19 \times \frac{3}{5}) = - 8.314 R e g a r d s$

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