The chemical formula of Iron (III) carbonate is :

F e_{2} (C O_{3})_{2}

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F e_{2} (C O_{3})

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F e_{2} (C O_{3})_{3}

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F e (C O_{3})_{2}

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Solution

The correct option is C $F e_{2} (C O_{3})_{3}$
In Iron(III) carbonate, iron has a valency of $+ 3$ and the valency of carbonate ion is $- 2.$ Therefore by cross multiplying the valency we get $F e_{2} (C O_{3})_{3}$

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