The chemical formula of siderite :

F e_{2} O_{3}

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F e_{3} O_{4}

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F e C O_{3}

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M n O_{2}

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Solution

The correct option is D $F e C O_{3}$
Siderite - $F e C O_{3}$
Magnetite - $F e_{3} O_{4}$
Haemitite - $F e_{2} O_{3}$
Pyrolusite - $M n O_{2}$

Hence, the correct option is $C$

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Similar questions

F e_{3} O_{4} + {M n O}_{4}^{-} \to F e_{2} O_{3} + M n O_{2}

F e_{3} O_{4}

F e_{2} O_{3}

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