The chemical formula of the oxyacid of chlorine in which chlorine exhibits its highest oxidation state is:

H O C l

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H C l O_{2}

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H C l O_{3}

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H C l O_{4}

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Solution

The correct option is D $H C l O_{4}$
$H C I O_{4}$ has highest oxidation state of chlorine i.e + 7

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Similar questions

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O_{4}, H O C l, C l F_{3}, H C l O_{3}

{H C l O}_{4}

{H C l O}_{3}

{H C l O}_{2}

H O C l

H C l O_{4}

H C l O_{3}

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