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Question

The chief ore of Zn is the sulphide, ZnS. The ore is concentrated by froth floatation process and then heated in air to convert ZnS to ZnO.
2ZnS+3O280%−−→2ZnO+2SO2
ZnO+H2SO4100%−−−→ZnSO4+H2O
2ZnSO4+2H2O80%−−→2Zn+2H2SO4+O2
The number of moles of ZnS required to produce 2 moles of Zn will be:

A
3.125
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B
2
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C
2.125
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D
4
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Solution

The correct option is A 3.125
Let the moles of ZnS taken is n

In the first step 80% of reaction is completed.
Then, amount OF ZnO formed is
n× 80100 = 0.8n

In the second step 100 % of reaction is completed.
Then, amount of ZnSO4 formed is
0.8n× 100100 = 0.8n

In the third step 80 % of reaction is completed.
Then, amount of Zn formed is
0.8n× 80100 = 0.64n

Given
0.64n must be equal to the 2 moles of Zn
i.e 0.64n = 2
n =3.125



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