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Standard XII

Chemistry

Copper II Sulphate

The chocolate...

Question

The chocolate coloured precipitate is_________.

F e_{2} [F e (C N)_{6}]

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C u_{2} [F e (C N)_{6}]

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H g S O_{4}

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[F e (H_{2} O)_{5} (N O)] S O_{4}

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Solution

The correct option is C $C u_{2} [F e (C N)_{6}]$
With potassium ferrocyanide solution $C u^{+ 2}$ forms $C u_{2} [F e (C N)_{6}]$ chocolate color ppt.

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Similar questions

Q. With

C u^{2 +}

ions

[F e (C N)_{6}]^{4 -}

gives

C u_{2} [F e (C N)_{6}]

(Cupric ferrocyanide). The colour of

C u_{2} [F e (C N)_{6}]

is?

Q. Mineral (A)

d i l . H_{2} S O_{4} ⟶

(B) + (C) + (D) (gas)
(D) +

C H_{3} C O O)_{2} P b △ ⟶

black ppt

(B) + (C) (D) \to

E (black ppt) separated from (C) by filtration
(E) +

H N O_{3} d i l . △ \to

(F) blue coloured solution
(F) +

K_{4} [F e (C N)_{6}] ⟶

K_{3} [F e (C N)_{6}] ⟶

(H) blue

A to H are identified as: (A) :

C u F e S_{2}

, (B) :

C u S O_{4}

F e S O_{4}

(D) :

H_{2} S

(E) :

C u S

(F) :

C u (N O_{3})_{2}

(G) :

C u_{2} [F e (C N)_{6}]

(H) :

K F e^{I I} [F e^{I I I} (C N)_{6}]

, Turnbull's blue

Show the above reaction.

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:
(a) $N a_{4} [F e (C N)_{6}]$ (b) $F e_{4} [F e (C N)_{6}]^{3}$ (c) $F e_{2} [F e (C N)_{6}]$ (d) $F e_{3} [F e (C N)_{6}]_{4}$

Q. Arrange the following in increasing flocculating power for coagulation of positive sol.

[F e (C N)_{6}]^{- 4}, P O_{4}^{- 3}, S O_{4}^{- 2}, C l^{-}

Q. Chocolate brown precipitate (A) is formed when aq.

C u S O_{4}

reacts with

K_{4} [F e (C N)_{6}]

. What is the formula of A from the following?

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The chocolate coloured precipitate is_________.

The correct option is C Cu2[Fe(CN)6]With potassium ferrocyanide solution Cu+2 forms Cu2[Fe(CN)6] chocolate color ppt.

The correct option is C $C u_{2} [F e (C N)_{6}]$
With potassium ferrocyanide solution $C u^{+ 2}$ forms $C u_{2} [F e (C N)_{6}]$ chocolate color ppt.