The chord joining the points where x = p and x = q on the curve y=ax2+bx+c is parallel to the tangent at the point on the curve whose abscissa is
A
p+q2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
p−q2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
pq2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
noneofthese
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Ap+q2 For x=p,y=ap2+bp+c And for x=q,y=aq2+bq+c Slope=aq2+bq+c−ap2−bp−cq−p=a(q+p)+bdydx=2ax+b=a(q+p)+b (according to the question) ∴x=q+p2