The chord of contact of tangents drawn from any point on the circle x2+y2=a2 to the circle x2+y2=b2 touches x2+y2=c2, where a,b,c>0, then a,b,c are in
A
2b=a+c
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B
b=√ac
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C
b=2aca+c
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D
b2=a2+c2
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Solution
The correct option is Bb=√ac Equation of chord of contact drawn from the point (x1,y1) on x2+y2=a2 to the circle x2+y2=b2 will be given by xx1+yy1=b2 Also x12+y12=a2 As we know that it touches the circle x2+y2=c2 So, the distance from the origin will be, ∣∣∣−b2√x21+y21∣∣∣=c⇒b2=ac