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Question

The chord of contact of tangents from a point 'P' to a circle passes through Q. If  l1 and l2 are the lengths of the tangents from P and Q to the circle, then PQ is equal to


Solution

The correct option is C
P=(x1,y1) and (x2,y2) From P tangent to the given circle is xx1+yy1=a2 Since it passes through Q(x2,y2)
x1x2+y1y2=a2(1)
Now, l1=x21+y21a2,l2=x22+y22a2 and
PQ=(x2x1)2+(y2y1)2 i.el21+l22

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