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Question

The circle passing through (t,1), (1,t) and (t,t)
for all values of t passes through .........

A
(1,1)
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B
(1,1)
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C
(1,1)
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D
(1,1)
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Solution

The correct option is A (1,1)
Let x2+y2+2gn+2fy+c=0 eqn of circle.
So, (t,1) t2+2gt+2f+1+c=0(1)
(1,t) t2+2ft+2g+1+c=0(2)
(t,t) 2t2+2t(g+f)+c=0(3)
from (1) & (2)
(gf)t+(fg)=0
t=t1
So, P (t,t) is (1,1).
So, circles passing through (1,t),(t,1) and (t,t) always passes through (1,1).

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