The correct option is A (1,1)
Let x2+y2+2gn+2fy+c=0 eqn of circle.
So, (t,1) ⇒t2+2gt+2f+1+c=0−−−−(1)
(1,t) ⇒t2+2ft+2g+1+c=0−−−−(2)
(t,t) ⇒2t2+2t(g+f)+c=0−−−−(3)
from (1) & (2)
(g−f)t+(f−g)=0
t=t1
So, P (t,t) is (1,1).
So, circles passing through (1,t),(t,1) and (t,t) always passes through (1,1).