The circle $x^{2} + y^{2} - 3 x - 4 y + 2 = 0$ cuts $x$ -axis

(2, 0), (- 3, 0)

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(3, 0), (4, 0)

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(1, 0), (- 1, 0)

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(1, 0), (2, 0)

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Solution

The correct option is D $(1, 0), (2, 0)$
$x^{2} + y^{2} - 3 x - 4 y + 2 = 0$

x-axis will be cut when $y = 0$

put $y = 0$

$x^{2} - 3 x + 2 = 0$

$(x - 2) (x - 1) = 0$

$x = 1, 2$

points $(1, 0), (2, 0)$
D is correct.

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The circle x2+y2−3x−4y+2=0 cuts x-axis

The correct option is D (1,0),(2,0)x2+y2−3x−4y+2=0 x-axis will be cut when y=0put y=0x2−3x+2=0 (x−2)(x−1)=0x=1,2points (1,0),(2,0)D is correct.

The circle $x^{2} + y^{2} - 3 x - 4 y + 2 = 0$ cuts $x$ -axis

The correct option is D $(1, 0), (2, 0)$
$x^{2} + y^{2} - 3 x - 4 y + 2 = 0$

x-axis will be cut when $y = 0$

put $y = 0$

$x^{2} - 3 x + 2 = 0$

$(x - 2) (x - 1) = 0$

$x = 1, 2$

points $(1, 0), (2, 0)$
D is correct.