The circle $x^{2} + y^{2} + 4 x - 7 y + 12 = 0$ cuts an intercept on y-axis is equal to

7

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4

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3

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1

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Solution

The correct option is D $1$
$x^{2} + y^{2} + 4 x - 7 y + 12 = 0$

$x = 0$

$y^{2} - 7 y + 12 = 0$

$y^{2} - 4 y - 3 y + 12 = 0$

$y (y - 4) - 3 (y - 4) = 0$

$(y - 3) (y - 4) = 0$

$y = 3, 4$

$(0, 3)$ $(0, 4)$

Intercept $= 4 - 3 = 1$ unit.

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