$T h e c i r c l e s x^{2} + y^{2} - 6 x + 6 y + 17 = 0 a n d x^{2} + y^{2} - 6 x - 2 y + 1 = 0, a c o m m o n e x t e r i o r t a n g e n t i s d r a w n t h u s f o r m i n g a c u r v i l i n e a r t r i a n g l e . T h e r a d i u s o f t h e c i r c l e i n s c r i b e d i n t h i s t r i a n g l e i s$

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Solution

The correct option is D

$T h e g i v e n c i r c l e s a r e t o u c h i n g e a c h o t h e r e x t e r n a l l y . x = \frac{3}{{(1 + \sqrt{3})}^{2}} = \frac{3}{2} (2 - \sqrt{3})$

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