Question

The circuit given uses ideal opamps. The current I $(in\mu A$) drawn from the source $V_s$ is ______________
(Answer upto one decimal place)

• A. -70.7

Answer 1

The correct option is A -70.7




$V_1=\frac{-18}{9}\times 1=-2Volt$


$I^{\prime }=\frac{2+2}{4k\Omega }=1mA$
$V_2=1k\times I^{\prime }+2$
$=1k\times 1m+2$
$=1+2=3V$
$I=\frac{1}{9k}+\frac{1-3}{11k}=(\frac{1}{9}-\frac{2}{11})mA$
$=-0.0707mA=-70.7\mu A$