The circuit shown here is used to compare the e.m.f.'s of the cells E1 and E2(E1>E2). When the galvanometer is connected to E1, the null point is at C. When the galvanometer is connected to E2, the null point will be
A
to the left of C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
to the right of C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
at C itself
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
no where on AB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A to the left of C Since E∝l. So, for E1>E2 we have l1>l2 and hence null point will be obtained at shorter length i.e., to the left of C.
Hence, the correct answer is (A).