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Question

The circuit shown here is used to compare the e.m.f.'s of the cells E1 and E2 (E1>E2). When the galvanometer is connected to E1, the null point is at C. When the galvanometer is connected to E2, the null point will be


A
to the left of C
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B
to the right of C
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C
at C itself
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D
no where on AB
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Solution

The correct option is A to the left of C
Since El. So, for E1>E2 we have l1>l2 and hence null point will be obtained at shorter length i.e., to the left of C.
Hence, the correct answer is (A).

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