Question

The circuit shown in the figure contains two diodes $D_1$ and $D_2$ each with a forward resistance of $50\Omega$ and with infinite backward resistance. If the battery voltage is $6V$, the current through the $100\Omega$ resistance (in $A$) is:

• A. Zero
• B. $0.02$
• C. $0.03$
• D. $0.036$

Answer 1

The correct option is B $0.02$

$D_1\to F.B\left(forwardbias\right),D_2\to R.B\left(reversebias\right)$
So $D_1$ can be considered as a resistance of $50\Omega$ and $D_2$ as open device.

From ohms law

$\text{I}=\frac{V_{\text{net}}}{R_{net}}\text{I}=\frac{6}{300}$

$=0.02A$