The circuit shown in the figure contains two diodes each with a forward resistance of $50$ ohms and with infinite backward resistance. If the battery voltage is $6$ V, the current through the $100$ ohm resistance (in Amperes) is?

Zero

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0.02

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0.03

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0.036

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Solution

The correct option is B $0.02$
Owy Diode $D$ , will allow the current to pass through as it is forward biased
So current through $100 Ω$ resistance is $\to$
Total Resistance $= 150 + 50 + 100 = 300 Ω$
Current $I = \frac{6}{300} = 0.02 Ω$

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The circuit shown in the figure contains two diodes $D_{1}$ and $D_{2}$ each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6V, the current through the 100 ohm resistance (in Amperes) is:

The circuit shown in the figure contains two diodes $D_{1}$ and $D_{2}$ each with a forward resistance of $50 Ω$ and with infinite backward resistance. If the battery voltage is $6 V$ , the current through the $100 Ω$ resistance (in $A$ ) is: