The circuit shown in the figure contains two diodes each with a forward resistance of 50- with infinite backwards resistance- If the battery voltage is 6V- the current through the 100-in amperes is

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The circuit s...

Question

The circuit shown in the figure contains two diodes each with a forward resistance of $50 Ω$ with infinite backwards resistance. If the battery voltage is 6V, the current through the $100 Ω$ (in amperes) is

zero

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0.03

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0.02

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0.036

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Solution

The correct option is B 0.02
Given that the resistance of diode $D_{1}$ is $50 Ω,$
Diode $D_{2}$ has infinite backward resistance, so the current passing through diode $D_{2}$ will be $0$
So the entire current will pass through diode $D_{1} .$
The voltage given is $6 V$ and the net resistance is $100 + 150 + 50 = 300 Ω$
The current passing through $100 Ω$ resistance is $\frac{6}{300} = 0.02 A .$
Therefore the correct option is $C .$

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Similar questions

The circuit shown in the figure contains two diodes $D_{1}$ and $D_{2}$ each with a forward resistance of $50 Ω$ and with infinite backward resistance. If the battery voltage is $6 V$ , the current through the $100 Ω$ resistance (in $A$ ) is:

Q. The circuit shown given contains two ideal diodes, each with a forward resistance of

50 Ω

. If the battery voltage is

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V, the current through the

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resistance (in Amperes) is?

The circuit shown in the figure contains two diodes $D_{1}$ and $D_{2}$ each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6V, the current through the 100 ohm resistance (in Amperes) is: