The circular boundary of the concave mirror subtends a cone of half angle θ at its centre of curvature. The minimum value of θ for which ray incident on this mirror parallel to the principal axis suffers reflection more than once is
A
30∘
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B
45∘
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C
60∘
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D
75∘
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Solution
The correct option is B45∘ For minimum θ at with reflection happens twice can be considered as shown below,
As incident ray is parallel to principal axis, we can say that i=r=θ
From triangle ABC, 90+2θ=180∘ 2θ=90∘ θ=45∘