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Electric field due to Charge Distribution - I

The circular ...

Question

The circular disk of radius 4 m with a charge density is enclosed by surface S.
$p_{s} = 12 sin ϕ m C / m^{2}$

A

48 μ C

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B

12 μ C

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C

3 μ C

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D

0

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Solution

The correct option is D 0
Total charge enclosed,

$Q = \int_{0}^{2 π} \int_{0}^{4} (12 sin ϕ) r d r d ϕ$

$= 0$

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