Question

The Circular scale of a screw gauge has 80 equal divisions, and its pitch is 2 mm. The least count of screw gauge is

• A. 0.01 mm
• B. 0.25 mm
• C. 0.04 mm
• D. 0.025 mm

Answer 1

The correct option is D 0.025 mm

Given,
$80CSD=2mm$
$\Rightarrow 1CSD=\frac{2}{80}mm=0.025mm$
$\therefore$ Least count = $1CSD=0.025mm$