Question

The circumcentre of the triangle formed by $A(1,2),B(-2,2),C(1,5)$ is

• A. $(1,2)$
• B. $(-2,2)$
• C. $(1,5)$
• D. $(\frac{-1}{2},\frac{7}{2})$

Answer 1

The correct option is D $(\frac{-1}{2},\frac{7}{2})$

Circumcentre of $\Delta$ABC

$A(1,2);B(-2,2),C(1,5)$

$\Delta$ABC is right angle at 'A', so

circumcentre is mid-point of BC

$\Rightarrow C=(\frac{1+(-2)}{2},\frac{2+5}{2})$

$=(\frac{-1}{2},\frac{7}{2})$.