The circumcentre of the triangle formed by $A (1, 2), B (- 2, 2), C (1, 5)$ is

(1, 2)

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(- 2, 2)

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(1, 5)

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(- \frac{1}{2}, \frac{7}{2})

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Solution

The correct option is B $(- \frac{1}{2}, \frac{7}{2})$
Since $Δ A B C$ is right angled triangle
circumcentre $=$ mid $-$ point of BC
$= (\frac{- 1}{2}, \frac{7}{2})$ .

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