The circumcentre of the triangle formed by the lines $x y + 2 x + 2 y + 4 = 0$ and $x + y + 2 = 0$ is :

(0, 0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(- 2, - 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(- 1, - 1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(- 1, - 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(- 1, - 1)$
$x y + 2 x + 2 y + 4 = 0$
$(x + 2) (y + 2) = 0$
$x = - 2$ and $y = - 2$ ...........(A,B,C are the intersection points of these lines)
Circum centre of triangle $A B C$ is mid-point of $C$ & $B$
Because right angle is formed by semi circle
Centre $C = (- 1, 1) .$

Suggest Corrections

Similar questions

x y + 2 x + 2 y + 4 = 0

x + y + 2 = 0

2 x^{2} - x y - y^{2} + x + 2 y - 1 = 0

x + y + 1 = 0

l^{2} + m^{2} = 1,

l^{2} + m^{2} = 1,

x + y = 0, x - y = 0

l x - m y = 1

l

m

l^{2} + m^{2} = 1

Join BYJU'S Learning Program