The circumcentre of the triangle having vertices as A(0,0), B(0,3) and C(4,0) is

(2, \frac{3}{2})

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(\frac{3}{2}, 2)

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(2, 0)

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(0, \frac{3}{2})

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Solution

The correct option is A $(2, \frac{3}{2})$
The triangle formed by the given vertices is a right angled triangle. The circumcentre of a right angled triangle is the mid point of the hypotenuse, which is $(2, \frac{3}{2})$

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The circumcentre of the triangle having vertices as A(0,0), B(0,3) and C(4,0) is

The correct option is A (2,32)The triangle formed by the given vertices is a right angled triangle. The circumcentre of a right angled triangle is the mid point of the hypotenuse, which is (2,32)

The correct option is A $(2, \frac{3}{2})$
The triangle formed by the given vertices is a right angled triangle. The circumcentre of a right angled triangle is the mid point of the hypotenuse, which is $(2, \frac{3}{2})$