Question

The circumcentre of the triangle with vertices (8, 6), (8, -2) and (2, -2) is at the point

• A. (2, -1)
• B. (1, - 2)
• C. (5, 2)
• D. (2, 5)
• E. (4, 5)

Answer 1

Answer: (C)

(5, 2)

The triangle formed by the points $A(8,6)$ $B(8,-2)$ and $C(2,-2)$ is a right angles triangle forming a right angle at $B$.

So the circumcenntre of the triangle is the mid point of the other two points.

So the circumcentre $C$ is

$(\frac{8+2}{2},\frac{6-2}{2})(\frac{10}{2},\frac{4}{2})(5,2)$.

So option $C$ is correct.