The circumference of a circle exceeds its diameter by $180$ cm. Then the area of the circle

2772

c m^{2}

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4984

c m^{2}

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1848

c m^{2}

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5544

c m^{2}

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Solution

The correct option is B $5544$ $c m^{2}$
$G i v e n - t h e d i f f e r e n c e b e t w e e n t h e c i r c u m f e r e n c e C & t h e d i a m e t e r D o f a c i r c l e i s 180 c m . T o f i n d o u t - t h e a r e a o f t h e c i r c l e = ? S o l u t i o n - L e t t h e r a d i u s o f t h e c i r c l e b e r . T h e n t h e c i r c u m f e r e n c e C = 2 π r & t h e d i a m e t e r = D = 2 r . S o C - D = 180 ⟹ 2 π r - 2 r = 180 ⟹ 2 r (π - 1) = 180 ⟹ 2 r (\frac{22}{7} - 1) = 180 ⟹ r = 42 c m . S o t h e a r . c i r c l e = π r^{2} = \frac{22}{7} \times 42^{2} {c m}^{2} = 5544 {c m}^{2} . A n s - O p t i o n D .$

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