Question

The circumference of a circular playground is 528 m. Find the total expenditure of repairs of the ground at the rate of Rs. 1.50 per square metre $(\pi =\frac{22}{7})$

• A. 33264
• B. 33345
• C. 33456
• D. none of these

Answer 1

The correct option is A 33264

Perimeter of the playground$=528m$
$=>2\pi r=528$
$=>r=\frac{528\times 7}{22\times 2}$
$=>r=84$
Now, Area of the playground$=\pi r^2$
$=\frac{22}{7}\times 84\times 84$
$=22176m$
Therefore,
Total expenditure$=area\times 1.50$
$=22176\times 1.50$
$=33264$